Teyona Anderson: Bio, Height, Weight, Age, Measurements

Teyona Anderson is an American fashion model and is the winner of the twelfth cycle of America’s Next Top Model. She has appeared on the cover or been featured in many fashion magazines including Seventeen Magazine, Destiny Magazine, Glamour magazine (South Africa), Soul Magazine and Edgars Club Magazine. She has walked in Arise Cape Town Fashion Week and South Africa Fashion Week.

Teyona Anderson

Teyona Anderson Personal Details:
Date Of Birth: 27 April 1988
Birth Place: Woodstown, New Jersey, USA
Birth Name: Teyona Asia Anderson
Nickname: Teyona
Also known as: Asia Anderson
Zodiac Sign: Taurus
Occupation: Fashion model, Reality star
Nationality: American
Race/Ethnicity: Black
Religion: Unknown
Hair Color: Black
Eye Color: Dark Brown
Sexual Orientation: Straight

Teyona Anderson Body Statistics:
Weight in Pounds: 125.6 lbs
Weight in Kilogram: 57 kg
Height in Feet: 5′ 9½”
Height in Meters: 1.77 m
Body Build/Type: Slim
Body Measurements: 32-23-35 in (81-58.5-89 cm)
Breast Size: 32 inches (81 cm)
Waist Size: 23 inches (58.5 cm)
Hips Size: 35 inches (89 cm)
Bra Size/Cup Size: 32B
Feet/Shoe Size: 8.5 (US)
Dress Size: 4 (US)

Teyona Anderson Family Details:
Father: Unknown
Mother: Unknown
Spouse/Husband/Partner: Skurt Russell
Children: 1 (Daughter)
Siblings: Unknown

Teyona Anderson Education:
Not available

Teyona Anderson Facts:
*She was born on April 27, 1988 in Woodstown, New Jersey, USA.
*She was a contestant and winner of Cycle 12 of ANTM.
*She was nominated for the Choice Female Reality Star at the Teen Choice Awards in 2009.
*She is signed with Elite Model Management.
*Follow her on Instagram.